Question

Solution 27ijk - 99i²j³k³ + 108 i j⁴ k²=

Answer 1

Answer:

For K

2

SO

4

,

K

2

SO

4

⟶2K

+

+SO

4

2−

At eqm, 1−α 2α α [α= degree of dissociation of K

2

SO

4

]

∴ Vant Hoff factor (i)=

1

1−α+α+2α

=1+2α

Let the concentration be C of K

2

SO

4

∴ Concentration at equilibrium =C(1+2α)

For NaOH,

NaOH⟶Na

+

+OH

−

At eqm, 1−β β β

i=1−β+β+β=1+β

∴ Let the concentration also be C (since both solution are isotonic)

∴ Concentration at eqm= C(1+β)

Both solution are isotonic

∴C(1+2α)=C(1+β)

⇒1+2α=1+β=1+1 [∵β=1 i.e. 100% ionized]

⇒1+2α=2

⇒α=0.5

∴ Degree of ionisation of K

2

SO

4

in aqueous solution is 50% .