Math, asked by ayeshasiddiqa16, 1 year ago

.....................!!!solution??

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GovindRavi: i m not judging you people...your notifications disturbing me...aap logo k borad chal re h..you should be focussed on your studies...though two core exams ( Maths and Science ) are over
GovindRavi: but still prepare for rest rather texting here... you involve me too in this mess...so i am not going to text here at all...so njoy n hv fun...n gud luck for your coming xams..

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Answered by GovindRavi
2

Hope this hlp........

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Answered by shadowsabers03
1

         

\ \ \ \ \ \boxed{$LHS$} \\ \\ \Rightarrow\ \boxed{(csc\theta-\sin\theta)(\sec\theta-\cos\theta)(\tan\theta+\cot\theta)} \\ \\ \\ \Rightarrow\ \boxed{(\frac{1}{\sin\theta}-\sin\theta)(\frac{1}{\cos\theta}-\cos\theta)(\tan\theta+\frac{1}{\tan\theta})} \\ \\ \\ \Rightarrow\ \boxed{(\frac{1-\sin^2\theta}{\sin\theta})(\frac{1-\cos^2\theta}{\cos\theta})(\frac{1+\tan^2\theta}{\tan\theta})}

\Rightarrow\ \boxed{(\frac{\cos^2\theta}{\sin\theta})(\frac{\sin^2\theta}{\cos\theta})(\frac{\sec^2\theta}{\tan\theta})} \\ \\ \\ \Rightarrow\ \boxed{\frac{\cos^2\theta \cdot \sin^2\theta \cdot \sec^2\theta}{\sin\theta \cdot \cos\theta \cdot \tan\theta}} \\ \\ \\ \Rightarrow\ \boxed{\frac{\sin^2\theta}{\sin^2\theta}} \\ \\ \\ \Rightarrow\ \boxed{1} \\ \\ \Rightarrow\ \boxed{$RHS$}

$$\sf{Hence proved!}

$$\sf{Plz mark it as the brainliest. \\ \\ \\ Thank you. :-))}

         


shadowsabers03: Plz ask me if you've any doubts.
ayeshasiddiqa16: no thank it's very much clear to me now...!!☺
shadowsabers03: Okay. Thank you for marking my answer as the brainliest.
ayeshasiddiqa16: it was worth..!
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