Question

Solution:

All the sides of a square are equal and all the angle are right angle.

let side of square is a cm

We know that area of square is

To find the area of ABCD

Apply Pythagoras Theorem in ∆DAB



So,the paper to be used to make that kite is 968 sq-cm.

* No figure attached in the question,to calculate the area of coloured paper.

Hope it helps you.

Answer 1

Answer:

sorry please tell me answer of 2 no

Answer 2

Answer:

According to the figure, AC = BD = 44cm AO = 44/2 = 22cm BO = 44/2 = 22cm From ΔAOB, AB2 = AO2 + BO2 ⇒ AB2 = 222 + 222 ⇒ AB2 = 2 × 222 ⇒ AB = 22√ 2 cm Area of square = (Side)2 = (22√2)2 = 968 cm2 Area of each triangle (I, II, III, IV) = Area of square /4 = 968 /4 = 242 cm2 To find area of lower triangle, Let a = 28, b = 28, c = 14 s = (a + b + c)/2 ⇒ s = (28 + 28 + 14)/2 = 70/2 = 35. Area of the triangle = √s(s-a)(s-b)(s-c) = √35(35-28)(35-28)(35-14) = √35×7×7×21 = 49√15 = 189.77 cm2 Therefore, We get, Area of Red = Area of IV = 242 cm2 Area of Yellow = Area of I + Area of II = 242 + 242 = 484 cm2 Area of Green = Area of III + Area of lower triangle = 242 + 189.77 = 431.77 cm2Read more on Sarthaks.com - https://www.sarthaks.com/875199/how-much-paper-each-shade-needed-make-kite-given-in-fig-in-which-abcd-is-square-with-diagonal?show=875202#a875202