Math, asked by jin12344, 4 months ago

Solution and answer

The perimeter of a rectangle is twice the sum of its length and width. The perimeter of the rectangle is less than 40 units and its width is 8 units. Write an inequality sentence to find the possible lengths of the rectangle


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Answers

Answered by janala
3

Answer:

given:

perimeter of rectangle=2(sum of length and breadth)

let length be l and breadth be b

FORM EQUATION: 2(L+B)

GIVEN WIDTH IS 8 UNITS AND PERIMETER IS LESS THAN 40

= 2(l+8)= 39

= 2l+ 16=39

2l=39-16

2l= 23

l= 23/2

Answered by 1223448
0

Answer:

given:

perimeter of rectangle=2(sum of length and breadth)

let length be l and breadth be b

FORM EQUATION: 2(L+B)

GIVEN WIDTH IS 8 UNITS AND PERIMETER IS LESS THAN 40

= 2(l+8)= 39

= 2l+ 16=39

2l=39-16

2l= 23

l= 23/2

Step-by-step explanation:

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