Business Studies, asked by Anam1119, 8 months ago

Solution at a certain petrol pump, customer arrive in poisson process with an average time of 5 mins between arrivals. The time interval between servers at the petrol pump follows an exponential distribution and the mean time to service a unit is 2 mins. In queuing theory how we do the sums like by how much the flow of the customer be increased to justify the opening of another service point where the customer has to wait for 5 minutes for the service, find by how much time the flow of customer be increased to justify the opening of another service point where the customer has to wait for 5 minutes for the service?

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Answered by najiyashaikh1105
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Answer:

Solution at a certain petrol pump, customer arrive in poisson process with an average time of 5 mins between arrivals. The time interval between servers at the petrol pump follows an exponential distribution and the mean time to service a unit is 2 mins. In queuing theory how we do the sums like by how much the flow of the customer be increased to justify the opening of another service point where the customer has to wait for 5 minutes for the service, find by how much time the flow of customer be increased to justify the opening of another service point where the customer has to wait for 5 minutes for the service.hdhdjc jdjdjd djdjkd djdkd djkd d dkkddn.

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