Solution containing 25% hote 25% ethanol and 50% acetic acid by mass calculate mole fraction of
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hlo mate here is ur ans............
Let the mass of solution is 100g
Then, mass of H2O=25g
mass of ethanol =25g
mass of acetic acid =50g
Number of moles of water =25/18g/mol=1.4
Number of moles of ethanol =25/46g/mol=0.54
Number of moles of Acetic acid =50/60g/mol=0.8
Total number of moles =(1.4+0.54+0.8)=2.74
Now, mole fraction of water =1.4/2.74=0.51
mole fraction of Ethanol =0.54/2.74=0.197
mole fraction of acetic acid =0.8/2.74=0.291
hope this helps uh dear :)
pls mark as brainliest..........
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