Question

Solution contains 85.5 g of sucrose (C12,H22,011) in 250 cm^3. What is its molarity? A) 0.5 M...C) 0.25 M... B) 2M... D)1 M​

Answer 1

Answer:

The molecular formula of the disaccharide sucrose is C12H22O11. Its molecular weight is 342.3. A solution of 1M sucrose contains 342.3g/1000cm3. In your example the concentration of sucrose is 85.5g/250cm3 or 342g/1000cm3 or just about exactly a molarity of 1M.

Answer 2

Answer:

D)  1.0 M

Explanation:

The equation for molarity is

molarity

=

mol solute

L soln

We're given the volume is  

1.00

 

L

, so we just need to find the moles of solute (we're given grams) via the molar mass of sucrose (

342.30

 

g/mol

):

85.5

g sucrose

(

1

l

mol sucrose

342.30

g sucrose

)

=

0.250

 

mol sucrose

Therefore, we have

molarity

=

0.250

l

mol sucrose

1.00

l

L soln

=

0.250

M