Math, asked by manimaloutombam123, 17 hours ago

Solution
(exterior angle property)
-
(exterior angle property)
ZPTS = ZTPR + ZPRT
ZPTS = 95°+ 40°=135°
Side QT of ASQT is produced to P.
ZPTS = ZTSQ + ZSQT
135º = 75°+ZSQT
ZSQT = 135°-75° = 60°
Hence, ZSQT = 60°
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Exercise 11.2
1. Find the value of x using exterior angle property in the following figures :
(c)
(b)
(a)
A
A
L
X
х
30° DC
30°
50°N
70°C
°
С
35°
Q
M
E
B
D
(c
)
c
2. In the following figures, find the values of x and y:
(a)
(b)
A
A
y
ly
329
X
z
65​

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1

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1

Answer:

i can,t understand the questoin

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