Math, asked by renuarvindpraj56, 9 months ago

solution fast please​

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Answered by shreyagupta58
0

Step-by-step explanation:

i hope it will helpful for you

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Answered by shreya882426
0

Step-by-step explanation:

 \sqrt{3}  - 1 \div  \sqrt{3}  + 1 \\ = ( \sqrt{3}   - 1)( \sqrt{3}  - 1) \div  =  ( \sqrt{3}   + 1)( \sqrt{3}  - 1)  \\ =  ( \sqrt{3 }  - 1) {}^{2}   \div  ( { \sqrt{3} )}^{2}  -  {1}^{2}  \\  = 3 + 1 - 2 \sqrt{3}  \div 3 - 1 \\ =  4 - 2 \sqrt{3}  \div 2 \\  = 2 -  \sqrt{3}  \\ a  -  b \sqrt{3}  = 2 -  \sqrt{3}  \\ here \: a = 2 \: and \: b = 1

4 +  \sqrt{2}  \div 2 +  \sqrt{2} \\  = (4 +  \sqrt{2} )(2 -  \sqrt{2} ) \div (2 +  \sqrt{2} )(2 -  \sqrt{2} ) \\  = 8 - 4 \sqrt{2}  + 2 \sqrt{2}  - 2 \div  {2}^{2}  - ( { \sqrt{2} )}^{2}  \\  = 6 -  2\sqrt{2}  \div 4 - 2 \\ 6 - 2 \sqrt{2}  \div 2 \\  = 3 -  \sqrt{2}  \\ a -  \sqrt{b}  = 3 -  \sqrt{2}  \\ here \: a = 3 \: and \: b = 2

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