solution for 25a^4-40a^2+16
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the gn poly is

Let the Poly be zero
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ie

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Since roots are coincident these will repeat
Let the Poly be zero
ie
ie
ie
ie
Since roots are coincident these will repeat
Answered by
1
25a^4-40a^2+16
25a^4 - 20a^2 -20a^2 -16
(5a^2 - 4)(5a^2 - 4)
(5a^2 - 4 )^2 = 0
a^ 2 = 4/5
a = +-(4/5)^1/2
25a^4 - 20a^2 -20a^2 -16
(5a^2 - 4)(5a^2 - 4)
(5a^2 - 4 )^2 = 0
a^ 2 = 4/5
a = +-(4/5)^1/2
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