Question

solution for a-b/a²+b²​

Answer 1

Answer:

$\underline{\bold{\huge{\red[\boxed{ANSWER}}}}}$

Step-by-step explanation:

→ first a^2+b^2 is

  a² + b ² = (a + b)² - 2ab

= (a + b)(a + b) - 2ab

= a² + 2ab + b² - 2ab

= a² + b² + 2ab - 2ab by the Commutative Property of Addition.

= a² + b² + 2ab + (- 2ab) by the Definition of Subtraction.

= a² + b² + [2ab + (- 2ab)] by the Associative Property of Addition.

= a² + b² + 2[ab + (- ab)] by the Distributive Property.

= a² + b² + 2[0] by the Additive Inverse Property.

= a² + b² + 0 by the Multiplication Property of Zero.

= a² + b²

∴hence a^2+b^2 is proved

→ therefore from question a-b/a^2+b^2

  =a-b/(a+b)^2-2ab

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