Solution for
Cos70°/sin20°+cos36° cosec54°
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Cos(90-20)/sin20 + cos36 cosec(90-36)
=sin20/sin20 + cos36 * sec36
=1 + cos36 * 1/cos36
=1 + 1
=2
=sin20/sin20 + cos36 * sec36
=1 + cos36 * 1/cos36
=1 + 1
=2
riadavid29:
Thanks a lot!!
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2
Step-by-step explanation:
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