Solution for
Lim (x+y)²/x²+y²=?
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Answered by
3
Answer:
x°2+2xy+y°2/x°2+y°2 is your answer
Answered by
0
Answer:
2xy=0
Step-by-step explanation:
Pick any two numbers x and y with neither being 0. For example, x=1, y=2. Or x=5, y=10,000. As long as neither x nor y is 0, this statement will be false.
(2+1)2=22+12(2+1)2=22+12
32=5?32=5?
(4+4)2=42+42(4+4)2=42+42
82=32?82=32?
As for how I knew that x and y could not be 0, consider:
(x+y)2=x2+2xy+y2(x+y)2=x2+2xy+y2
So, if x or y is 0, that middle term is 0, and the statement is true for that pair. In other words:
x2+2xy+y2=x2+y2x2+2xy+y2=x2+y2
is only true when 2xy=0.
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