Question

Solution for pair of linear equation ^2x+^3y=0,^3x-^8y=0

Answer 1

Let's solve your system by substitution.

2x+3y=0;3x−8y=0


Step: Solve2x+3y=0for x:

2x+3y=0

2x+3y+−3y=0+−3y(Add -3y to both sides)

2x=−3y

2x/2=−3y/2(Divide both sides by 2)

x=−3/2y


Step: Substitute−32yforxin3x−8y=0:

3x−8y=0

3−3/2y−8y=0

−25/2y=0(Simplify both sides of the equation)

−25/2y−25/2=0−25/2(Divide both sides by (-25)/2)

y=0


Step: Substitute0foryinx=−3/2y:

x=−3/2y

x=−3/2(0)

x=0(Simplify both sides of the equation)


Answer:

x=0 and y=0


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