Solution for the empirical formula of compound is c2h5. it has vapour density of 29.determine relative molecular mass of the compound and hence its molecular formula
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12
V.D. = 29
Emperical formula mass = 12(2) + 5(1) = 29
n = given mass/ emperical formula mass.
= 2*29/29 =2 ( mass = 2* vapour density )
Molecular formula = n * emperical formula
= 2* C2H5
Molecular formula = C4H10
Emperical formula mass = 12(2) + 5(1) = 29
n = given mass/ emperical formula mass.
= 2*29/29 =2 ( mass = 2* vapour density )
Molecular formula = n * emperical formula
= 2* C2H5
Molecular formula = C4H10
Answered by
2
Answer:
vd = 29
so, n = mm/em
I. e. 2*29/29= 2
so, molecular mass =29*2=58
Mf = C4H10
Explanation:
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