Question

Solution for the problem the sum of ages p and q is 42 years.3 years back the age of p was 5 times the age of the q.Find the difference between the present ages of p and q

Answer 1

let p age be x

then q age is( 42-×)

x -5 years. 5

---------- : ---

42-x-5years 1

(37-x)

x-5 = 5 × 37 - 5x

x + 5x = 185 + 5

6x= 190

x = 190÷6

now solve for x