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AB=BC (GIVEN)
BP=BQ (GIVEN)
THEN , AP=CQ (because ab=bc and bp=bq)
BP=BQ (GIVEN)
THEN , AP=CQ (because ab=bc and bp=bq)
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AB = BC (given)
BP = BC (GIVEN)
THEN,
AB-BP = BC-BQ(as according to Euclid's postulate, equals minus equals is equals only)
AP = CQ..... hence proved.
BP = BC (GIVEN)
THEN,
AB-BP = BC-BQ(as according to Euclid's postulate, equals minus equals is equals only)
AP = CQ..... hence proved.
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