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Answer 1

Answer:

Given -: H= 11m

speed= 10m/s

angle= 37°

Explanation:

The formulas for the components Vx and Vy of the velocity and components x and y of the displacement are given by

Vx = V0 cos(θ)

Vy = V0 sin(θ) - g t

x = V0 cos(θ) t

y = V0 sin(θ) t - (1/2) g t2

In the problem V0 = 10m/s, θ = 37° and g = 9.8 m/s2.

The height of the projectile is given by the component y, and it reaches its maximum value when the component Vy is equal to zero. That is when the projectile changes from moving upward to moving downward.

Vy = V0 sin(θ) - g t = 0

solve for t

t = V0 sin(θ) / g

= 10 sin(37°) / 9.8 = -0.65 seconds

Find the maximum height by substituting 't' by 0.65 seconds in the formula for y

maximum height y (0.65) = 10 sin(37°)(0.65) - (1/2) (9.8) (0.65) 2 = 10.5 meters

sorry bro I don't know other parts