Question

solution give me fast​

Answer 1

Answer:

Step-by-step explanation:

LHS :-

⇒AB² + AC²

⇒AE² + BE² + AE² + EC²

⇒2 AE² + BE² + EC²

⇒ 2 AE² + (BD - ED )² + (ED + DC)²

⇒2 AE² + BD² + ED² - 2 BD ED + ED² + DC² + 2 ED DC ( 2 BD ED and 2 ED DC gets cancelled as BD = DC )

⇒ 2 AE² + BD² + 2 ED² + BD² ( BD = DC )

⇒ 2 AE² + 2 BD² + 2  ED²

⇒ 2 ( AE² + BD² + ED² )

⇒ 2 ( AD² + BD² )

Hence Proved