Question

Solution give plese​

Answer 1

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${( - \frac{5}{8} )}^{x - 9} = 1 \\ = > {( - \frac{5}{8} )}^{x - 9} = {( - \frac{5}{8} )}^{0} [∵ {a}^{0} = 1]$

Equating the bases, we get,

$x - 9 = 0 \\ = > x = \small\sf\red{9}$

Answer 2

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$$\begin{lgathered}{( - \frac{5}{8} )}^{x - 9} = 1 \\ = > {( - \frac{5}{8} )}^{x - 9} = {( - \frac{5}{8} )}^{0} [∵ {a}^{0} = 1]\end{lgathered}$$

Equating the bases, we get,

$$\begin{lgathered}x - 9 = 0 \\ = > x = \small\sf\red{9}\end{lgathered}$$