solution in e^2x-5=2^x-3
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Answer:
Consider the given equation.
e2x+e−2x+ex+e−x=3e−2x+3ex
e4x+1+e3x+ex=3+3e3x
e3x(ex−2)+1(ex−2)=0(e3x+1)(ex−2)=0
Here, e3x+1=0
e3x=−1
This is not possible, so, this can't be the solution of the given equation.
ex−2=0ex=2x=ln2
So, there is only one solution of this equation.
Hence, option c is the correct option.
Step-by-step explanation:
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