Math, asked by sadlifeee, 2 months ago

solution in e^2x-5=2^x-3

Answers

Answered by cool5257boy
3

Answer:

Consider the given equation.

e2x+e−2x+ex+e−x=3e−2x+3ex

e4x+1+e3x+ex=3+3e3x

e3x(ex−2)+1(ex−2)=0(e3x+1)(ex−2)=0

Here, e3x+1=0

e3x=−1

This is not possible, so, this can't be the solution of the given equation.

ex−2=0ex=2x=ln2

So, there is only one solution of this equation.

Hence, option c is the correct option.

Step-by-step explanation:

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