Question

Solution is prepared by adding 2 gram of substance a to 18 gram of water calculate the mass present of the solute

Answer 1

Explanation:

% mass ( solute)= mass(solute)/ mass(solution)×100

= 2/18+2×100

= 2/20×100

=2×5

= 10gm.

Answer 2

Answer:

Mass of solute = 2 grams

Mass of solvent = 18 grams

Mass of Solution = Mass of solute + Mass of solvent

=> Mass of Solution =( 2 +18) grams

=> Mass of Solution = 20 grams

Masspercentage=

MassofSolution

MassofSolute ×100

or

Masspercentage=

MassofSolution

MassofSolventb×100

:⟶Mass percentage of solute= 20/ 2 ×100

\tt \longrightarrow Mass \: percentage \: of \: solute = \dfrac{1}{1} \times 10 \: = 10 \%⟶Masspercentageofsolute=

1

1

×10=10%

\tt \longrightarrow Mass \: percentage \:of \: solvent= \dfrac{18}{20} \times 100⟶Masspercentageofsolvent=

20

18

×100

\tt \longrightarrow Mass \: percentage \:of \: solvent= \dfrac{9}{1} \times 10 = 90\%⟶Masspercentageofsolvent=

1

9

×10=90%

Answer :

mass percentage of solute = 10%

mass percentage of solvent = 90%