Solution is prepared by adding 2 gram of substance a to 18 gram of water calculate the mass present of the solute
Answers
Explanation:
% mass ( solute)= mass(solute)/ mass(solution)×100
= 2/18+2×100
= 2/20×100
=2×5
= 10gm.
Answer:
Mass of solute = 2 grams
Mass of solvent = 18 grams
Mass of Solution = Mass of solute + Mass of solvent
=> Mass of Solution =( 2 +18) grams
=> Mass of Solution = 20 grams
Masspercentage=
MassofSolution
MassofSolute ×100
or
Masspercentage=
MassofSolution
MassofSolventb×100
:⟶Mass percentage of solute= 20/ 2 ×100
\tt \longrightarrow Mass \: percentage \: of \: solute = \dfrac{1}{1} \times 10 \: = 10 \%⟶Masspercentageofsolute=
1
1
×10=10%
\tt \longrightarrow Mass \: percentage \:of \: solvent= \dfrac{18}{20} \times 100⟶Masspercentageofsolvent=
20
18
×100
\tt \longrightarrow Mass \: percentage \:of \: solvent= \dfrac{9}{1} \times 10 = 90\%⟶Masspercentageofsolvent=
1
9
×10=90%
Answer :
mass percentage of solute = 10%
mass percentage of solvent = 90%