Question

Solution : m (arcNS) = 125°
m (arc EF) = 37° Given
LNMS has its a vertex in the exterior of the circle and intercept are EF and are NS
NMS = 2 [m (arc NS) - ]]
NMS=2x[O
]
NMS=1 X 88
ZNMS=​

Answer 1

Answer:

NMS=2[ m(arc NS)-m(arc EF)]

NMS=2×[125-37]

NMS=1×88

ZNMS=88