Question

Solution :
Method I : 5x - 3y =
5x - 3y = 8... (1)
3x + y = 2... (II) X3
Multiplying
both sides of
equation (II) by 3.
9x + 3y = 6 ... (III)
5x - 3y = 8... (1)
Now let us add equations (1)
and (III)
5x - 3y = 8
+ 9x + 3y = 6
14x = 14
:: x = 1
substituting x = 1 in equation (I
3x + y = 2 .
3x1 + y = 2
3+ y = 2
y = -1
solution is x = 1, y = -1; it is a
written as (x, y) = (1, -1)​

Answer 1

Answer:

this question was very long due to send my copy please give me a thanks please