Solution of 0.1 N NH4OH and 0.1 N NH4CI
has pH 9.25. Then pKb, of NH4OH is
Answers
Answered by
1
Answer:
NH
4
OH (a base) and NH
4
Cl (a salt) undergoes dissociation as follows:-
NH
4
OH⇌NH
4
+
+OH
−
NH
4
Cl→NH
4
+
+Cl
−
Due to the common ion effect, the reaction of dissociation of NH
4
OH shifts to the left.
Here, the given information is :-
Concentration of salt NH
4
Cl = 0.1N
Concentration of the base NH
4
OH=0.N
pH of the solution is 9.25
∴ pOH= 14 - pH = 14 - 9.25 = 4.75
We know that,
pOH=pK
b
+log
[base]
[salt]
(but here concentration of salt = concentration of base and [log
10
(1)=0])
∴pOH=pK
b
=4.75
Hence, the correct answer is option (B).
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