Question

solution of 0.78gmBenzene and 0.92gm of toluene
v. p. of pure benzene = 400 mmHg.
V.p. of pure toluene = 200 mm Hg
molar mass of Benzene = 78gm
Molaremass of toluene= 92gm
find total v. p. of solution? ​

Answer 1

Answer:

Apply Raoult law

Explanation:

Total v.p = x1P1 + x2P2

where x1 is mole fraction of toluene P1 is v.p. of toluene

x2 is mole fraction of benzene P2 is v.p. of toluene

mole fraction = number of moles / total number of moles

Moles = weight of substance / molar mass