Question

solution of 2x+y =1 and 3x -2y =5​

Answer 1

Answer:

answer is x=6

Step-by-step explanation:

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Answer 2

AnsWer :

• X = 1.
• Y = -1.

Given :

• 2x +y = 1.
• 3x - 2y = 5.

Solution :

We have, Pair of linear equation.

$\tt \dagger \: \: \: 2x + y = 1. \: \: \: \: \: - (1)$

$\tt \dagger \: \: \: 3x - 2y = 5. \: \: \: \: \: - (2)$

$\rule{90}1$

Taking Equation, (1)

$\tt \longmapsto 2x + y = 1.$

$\tt \longmapsto y = 1 - 2x. \: \: \: \: \: - (3)$

Putting the value of y in equation (2) , We get.

$\tt \longmapsto 3x - 2y = 5.$

$\tt \longmapsto 3x - 2(1 - 2x) = 5.$

$\tt \longmapsto 3x - 2 + 4x = 5.$

$\tt \longmapsto 7x = 5 + 2.$

$\tt \longmapsto 7x = 7.$

$\tt \longmapsto x = \frac{7}{7}$

$\tt \longmapsto x = 1.$

$\rule{90}1$

Now, Putting the value of x in equation (3) , We get.

$\tt \longmapsto y = 1 - 2x.$

$\tt \longmapsto y = 1 - 2(1).$

$\tt \longmapsto y = 1 - 2.$

$\tt \longmapsto y = - 1.$

Therefore, the value of x be 1 and y be -1.

$\rule{200}3$

Let's Verify :

Taking Equation (1)

$\tt \longmapsto 2x + y = 1.$

$\tt \longmapsto 2(1) + (-1) = 1.$

$\tt \longmapsto 2 - 1 = 1.$

$\tt \longmapsto 1 = 1.$

LHS = RHS.

$\rule{30}1$

Taking Equation (2)

$\tt \longmapsto 3x - 2y = 5.$

$\tt \longmapsto 3(1) - 2(-1) = 5.$

$\tt \longmapsto 3 + 2 = 5.$

$\tt \longmapsto 5= 5.$

LHS = RHS.