solution of 3x/4-7/4=5x+12 is
Answers
Step-by-step explanation:
How to solve your question
Your question is
3
4
−
1
⋅
7
4
=
5
+
1
2
\frac{3x}{4}-1 \cdot \frac{7}{4}=5x+12
43x−1⋅47=5x+12
Solve
1
Multiply the numbers
3
4
−
1
⋅
7
4
=
5
+
1
2
\frac{3x}{4}{\color{#c92786}{-1}} \cdot {\color{#c92786}{\frac{7}{4}}}=5x+12
43x−1⋅47=5x+12
3
4
−
7
4
=
5
+
1
2
\frac{3x}{4}{\color{#c92786}{-\frac{7}{4}}}=5x+12
43x−47=5x+12
2
Add
7
4
\frac{7}{4}
47
to both sides of the equation
3
4
−
7
4
=
5
+
1
2
\frac{3x}{4}-\frac{7}{4}=5x+12
43x−47=5x+12
3
4
−
7
4
+
7
4
=
5
+
1
2
+
7
4
\frac{3x}{4}-\frac{7}{4}+{\color{#c92786}{\frac{7}{4}}}=5x+12+{\color{#c92786}{\frac{7}{4}}}
43x−47+47=5x+12+47
3
Simplify
Add the numbers
Add the numbers
3
4
=
5
+
5
5
4
\frac{3x}{4}=5x+\frac{55}{4}
43x=5x+455
4
Subtract
5
5x
5x
from both sides of the equation
3
4
=
5
+
5
5
4
\frac{3x}{4}=5x+\frac{55}{4}
43x=5x+455
3
4
−
5
=
5
+
5
5
4
−
5
\frac{3x}{4}{\color{#c92786}{-5x}}=5x+\frac{55}{4}{\color{#c92786}{-5x}}
43x−5x=5x+455−5x
5
Simplify
Combine like terms
3
4
−
5
=
5
5
4
\frac{3x}{4}-5x=\frac{55}{4}
43x−5x=455
6
Multiply all terms by the same value to eliminate fraction denominators
3
4
−
5
=
5
5
4
\frac{3x}{4}-5x=\frac{55}{4}
43x−5x=455
4
(
3
4
−
5
)
=
4
⋅
5
5
4
4(\frac{3x}{4}-5x)=4 \cdot \frac{55}{4}
4(43x−5x)=4⋅455
7
Simplify
Distribute
Cancel multiplied terms that are in the denominator
Combine like terms
Multiply the numbers
−
1
7
=
5
5
-17x=55
−17x=55
8
Divide both sides of the equation by the same term
−
1
7
=
5
5
-17x=55
−17x=55
−
1
7
−
1
7
=
5
5
−
1
7
\frac{-17x}{{\color{#c92786}{-17}}}=\frac{55}{{\color{#c92786}{-17}}}
−17−17x=−1755
9
Simplify
Cancel terms that are in both the numerator and denominator
Divide the numbers
=
−
5
5
1
7
x=-\frac{55}{17}
x=−1755
Solution
=
−
5
5
Answer:
ANSWER IS X=-55/17
Step-by-step explanation:
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