Solution of a.[b×(3a-2b)]
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Answered by
1
Hii....
a. [ b×( 3a- 2b )] = a. [ b× 3a - b× 2b ]
..... b× b = 0 ..
= a. ( b × 3a ) ...
= 0 ....
As a. ( b× a ) = b. ( c×b ) = c. ( b×c ) = 0 ...
Hope it helps...
a. [ b×( 3a- 2b )] = a. [ b× 3a - b× 2b ]
..... b× b = 0 ..
= a. ( b × 3a ) ...
= 0 ....
As a. ( b× a ) = b. ( c×b ) = c. ( b×c ) = 0 ...
Hope it helps...
Answered by
1
a.[b×(3a-2b)]
=a.[3ab-2b^2]
=3a^2b-2ab^2
this is the answer...
=a.[3ab-2b^2]
=3a^2b-2ab^2
this is the answer...
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