Question

solution of all prompts for class10 2015-2016

Answer 1

Answer:

Initial capacitance C

1

=

d

Aϵ

0

Final capacitance C

2

=

1.5d

Aϵ

0

=

3d

2Aϵ

0

Since the capacitor was isolated, the charge stored remains the same.

Thus work done=

2C

2

Q

2

−

2C

1

Q

2

=

4C

Q

2