solution of cubic eqn x3-x=6
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x3 - x = 6.
Or, x3 - x - 6 = 0.
Or, x3 - 2x2 + 2x2 - 4x + 3x - 6 = 0.
Or, x2(x-2) + 2x(x-2) + 3(x-2) = 0.
Or, (x-2)(x2 + 2x + 3) = 0.
Or, (x - 2) = 0/(x2 + 2x + 3) = 0.
Or, x - 2 = 0.
Or, x = 2.
Thus, x = 2.
Hope this helps,.
If helps, please mark it as brainliest ^_^
Dhirueagle:
please tell me this algorithm complete steps
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