Question

Solution of differential equation dy+ytanx.dx=y^2secx.dx

Answer 1

Answer:

Rewriting the given equation y-2(dy/dx) - y-1tanx

= - secx Let y-1 = v. Then -y2(dy/dx) = dv/dx Therefore, Multiplying

Eq. (1) by secx and integrating vsecx = ∫sec2xdx = tanx + c Thus, the required solution is secx/y = tanx +

Answer 2

Answer:

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Step-by-step explanation:

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