Solution of
dy /dx +y/x = logx
.
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Answered by
0
Answer:
y = x/2(logx - 1/2) + C
Step-by-step explanation:
Differential Equation
dy/dx + y/x = logx
I. F. = e^(Integration Symbol(1/x)dx)
= e^(logex)
= x
Multiplying by Integrating factor
x(dy/dx) + y = xlogx
Integrating with respect to x
y.x = Integration Symbol (x.logx dx)
xy = logx. x^2/2 - Integration Symbol ((x^2/2)(1/x)dx)
xy = x^2 logx/2 - (1/2) (x^2/2) + C
y = x/2(logx - 1/2) + C
Answered by
1
Answer is given in the pic.
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