solution of ethyl alcohol in water is 46% 5/8 calculate mole fraction of ethyl alcohol and water in the solution
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Water = H20
M of water = 2×1+16
= 18 g/mol
Ethyl Alcohol = C2H5OH
M of ethyl alcohol = 2×12+6+16
= 46 g/mol
46 % ethly alcohol solution so let us assume that 46 g ethanol is in 100 g solution
n = m/M
n of water = (100-46) /18
= 54/18
= 3 moles
n of ethanol = 46/46 = 1 mole
xa = na/na+nb
x of water = 3/(1+3)
= 3/4
x of ethanol = 1/4
I think it's correct
:-)
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