solution of example 3 plzz
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Hope this helps you and please mark as brainliest.
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[0010001111]... Hello User... [1001010101]
Here's your answer...
![log_{ {8}^{ \frac{1}{2} } }(x) = \frac{10}{3} \\ \frac{1}{ \frac{1}{2} } log_{8}(x) = \frac{10}{3} \\ log_{8}(x) = \frac{5}{3} log_{ {8}^{ \frac{1}{2} } }(x) = \frac{10}{3} \\ \frac{1}{ \frac{1}{2} } log_{8}(x) = \frac{10}{3} \\ log_{8}(x) = \frac{5}{3}](https://tex.z-dn.net/?f=+log_%7B+%7B8%7D%5E%7B+%5Cfrac%7B1%7D%7B2%7D+%7D++%7D%28x%29++%3D++%5Cfrac%7B10%7D%7B3%7D++%5C%5C++%5Cfrac%7B1%7D%7B+%5Cfrac%7B1%7D%7B2%7D+%7D++log_%7B8%7D%28x%29++%3D++%5Cfrac%7B10%7D%7B3%7D++%5C%5C++log_%7B8%7D%28x%29++%3D++%5Cfrac%7B5%7D%7B3%7D+)
Converting to exponential form...
![{8}^{ \frac{5}{3} } = x \\ x = {2}^{3 \times \frac{5}{3} } \\ x = {2}^{5} \\ x = 32 {8}^{ \frac{5}{3} } = x \\ x = {2}^{3 \times \frac{5}{3} } \\ x = {2}^{5} \\ x = 32](https://tex.z-dn.net/?f=+%7B8%7D%5E%7B+%5Cfrac%7B5%7D%7B3%7D+%7D++%3D+x+%5C%5C+x+%3D++%7B2%7D%5E%7B3+%5Ctimes++%5Cfrac%7B5%7D%7B3%7D+%7D++%5C%5C+x+%3D++%7B2%7D%5E%7B5%7D++%5C%5C++x+%3D+32)
[0110100101]... More questions detected... [010110011110]
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Here's your answer...
Converting to exponential form...
[0110100101]... More questions detected... [010110011110]
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shivam123443348:
plzz explain second step why we do .... 1/1/2 wala step
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