Question

Solution of h2o2 is 0.18 N percent then volume strength is

Answer 1

Answer:

VOLUME STRENGTH =Normality×5.6

Normality =  

5.6

Volumestrength

​  

 

Normality =  

5.6

5.6

​  

=1N

Answer 2

Solution of $H_2O_2$ is 0.18 N percent then volume strength is 1.008 Litres

Explanation:

Given

$H_2O_2$ solution of strength 0.18 N

To find out

Volume strength of $H_2O_2$

We know that

$\text{Normality of a solution}=\frac{\text{Weight}}{\text{Equivalent Weight}}$

Also, the equivalent weight of $H_2O_2$ = Molecular Weight/2

                                                                                 = 34/2 = 17

Hence,

$0.18=\frac{\text{Weight}}{17}$

$\implies \text{Weight}=0.18\times 17=3.06$ gram

Volume strength of $H_2O_2$ is Volume of Oxygen at STP as given by $H_2O_2$ on heating

The reaction is

$2H_2O_2\rightarrow 2H_2O+O_2$

2 moles of $H_2O_2$ gives 1 mole or 22.4 litres of $O_2$ at STP

or 68 grams of $H_2O_2$ gives 22.4 litres of $O_2$ at STP

Therefore, 3.06 grams of $H_2O_2$ will give

$=\frac{22.4}{68}\times3.06$ litres of $O_2$ at STP

$=1.008$ litres of $O_2$ at STP

Therefore, the volume strength of 0.18N $H_2O_2$ is 1.008 Litres

Hope this answer is helpful.

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