Question

Solution of h2so4 is labelled 40%.the density of the solution is 1.3gm/L. What is the concentration of the solution in % (m/v)?

Answer 1

Lets assume that the 40% is given as volume percentage.
40% H​2SO4 means that the 40 mL of H2SO4 is dissolved in water to make the solution 100 mL.
Thus, volume of H2SO4 = 40 mL
Since density = 1.3 g/mL
Then we can calculate the mass of H2SO4.
density = mass/volume
1.3 = mass/ 40
mass = 52 g
Now,
mass of H2SO4 = 52 g
and total volume of solution = 100
mass by volume percentage is the mass dissolved in 100 mL of the solution
Thus, m/v % = 52 %

Answer 2

Answer: The concentration of the solution in % (m/v) is 52%.

Explanation:

Solution of $H_2SO_4$ is labelled 40% that means in 100 grams of solution 40 grams of $H_2SO_4$ and 60 grams of water is present.

Mass of $H_2SO_4$ = 40 g

Density of the solution = 1.3 g.L

mass of the solution = 100 g

Volume of the solution = V

$density=\frac{mass}{volume}=1.3 g/L=\frac{100 g}{V}$

$V=\frac{100 g}{1.3 g/L}=76.9230 L$

$(m/v)\%=\frac{\text{Mass of the}H_2SO_4}{\text{Volume of the solution}}\times 100=\frac{40}{76.9230}\times 100=52\%$

The concentration of the solution in % (m/v) is 52%.