Question

Solution of inequality x^2 +x + l x l + 1 <= 0​

Answer 1

Answer:

x^2+x+|x|+1<=0

x^2+x<=-x-1

x^2<=-2x-1

x^2+2x+1<=0

x^2+x+x+1<<=0

x(x+1)+1(x+1)<=0

(x+1)^2<=0

x+1<=0

hence

x<=-1

solved

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