Question

solution of log 3 x minus 1 base 5 is greater than 1 is​

Answer 1

Hey MATE!!!

$log_{5}(3x - 1) > 1 \\ \\taking \: 5 \: other \: side \: and \: solving </em></strong><strong><em>\</em></strong><strong><em>\</em></strong><strong><em> logarithemic \: equation \: we \: </em></strong><strong><em>get</em></strong><strong><em> \\ \\ 3x - 1 > {5}^{1} \\ \\ 3x > 5 + 1 \\ \\ 3x > 6 \\ \\ x > \frac{6}{3} \\ \\ x > 2$

To satisfy the equation, x should achieve values greater than 2.

Hence x belongs to (2,∞).

Hope it helps

HAKUNA MATATA :))

Answer 2

Answer:

\begin{gathered}log_{5}(3x - 1) > 1 \\ \\taking \: 5 \: other \: side \: and \: solving \\ logarithemic \: equation \: we \: get \\ \\ 3x - 1 > {5}^{1} \\ \\ 3x > 5 + 1 \\ \\ 3x > 6 \\ \\ x > \frac{6}{3} \\ \\ x > 2\end{gathered}

log

5

(3x−1)>1

taking5othersideandsolving

logarithemicequationweget

3x−1>5

1

3x>5+1

3x>6

x>

3

6

x>2

To satisfy the equation, x should achieve values greater than 2.

Hence x belongs to (2,∞).

Step-by-step explanation:

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