Solution of NaOH prepared by dissolving 0.4 g in 10 liters of water. Calculate pH of this solution and the change in the pH if you take 100 ml of this solution and dilute it to 150 ml with distilled water, if you know that logarithms of 6.66 =0.823 *
4 points
Answers
Answered by
1
NaOH→Na + +OH −
Strong base completely dissociates, therefore [OH − ]= 400.4
mol/L=10 −2 M
Since,
[OH − ][H + ]=10 −14 M
[H + ]=10 −12 M
pH=−log([H + ])
pH=12
Answered by
0
Correct option is
A
12
NaOH→Na
+
+OH
−
Strong base completely dissociates, therefore [OH
−
]=
40
0.4
mol/L=10
−2
M
Since,
[OH
−
][H
+
]=10
−14
M
[H
+
]=10
−12
M
pH=−log([H
+
])
pH=12
Therefore option A is correct.
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