Question

solution of numerical calculate the voltage needed to balance an oil drop carrying 10 electron when located between the plates of capacitor which are 5mm apart. the mass of oil drop is 3 •10 the power-16 kg

Answer 1

Answer:

F

G

=3×10

−6

×10=3×10

−15

N

E=(

10e

mg

)=(

10×1.6×10

−19

3×10

−15

)=0.1875×10

4

V/m

V=Ed

=0.1875×10

4

×5×10

−3

=9.375volt

Explanation:

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