Solution of numerical when the pressure of the gas is doubled the velocity of sound in it is
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The speed of sound Cs depends on pressure (P) and density (ρ) as follows:
Cs =√(γP/ρ)
Where γ is the adiabatic constant ( the ratio between heat capacities at constant pressure and at constant volume =1.4 for air).
Assuming the air is an ideal gas, its density is inversely proportional to the absolute temperature (T in Kelvin), for constant pressure.
For T1 = 10◦C = 10 +273=283K, Cs = Cs1
Now if we increase the absolute temperature 4 fold to T2 = 4T1 =4*283K = 1132K
Then ρ will decrease 4 fold and hence Cs will double.
Cs2 = 2Cs
Now to get back to Celsius degrees: 1132 -273 = 859◦C
So, the answer is that at T = 859◦C the speed of sound will be double that at 10◦C
Cs =√(γP/ρ)
Where γ is the adiabatic constant ( the ratio between heat capacities at constant pressure and at constant volume =1.4 for air).
Assuming the air is an ideal gas, its density is inversely proportional to the absolute temperature (T in Kelvin), for constant pressure.
For T1 = 10◦C = 10 +273=283K, Cs = Cs1
Now if we increase the absolute temperature 4 fold to T2 = 4T1 =4*283K = 1132K
Then ρ will decrease 4 fold and hence Cs will double.
Cs2 = 2Cs
Now to get back to Celsius degrees: 1132 -273 = 859◦C
So, the answer is that at T = 859◦C the speed of sound will be double that at 10◦C
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