solution of pair of linear equations 3x+2y=11 and 2x+3y=4 is
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3x+2y=11. --->1
2x+3y=4. ---->2
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multiple equation 1 with 2
multiple equation 2 with 3
we get
6x+4y=22
6x+9y= 12
(-). (-). (-)
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-5x= -10
X= 2
substitute X= 2 in equation
6(2)+4y=22
12+4y=22
4y= 22-12
4y= 10
y= 10/4
y= 5/2
therefore
the Value of X= 2
the value of Y=5/2
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Answer:
3x+2y=11 ------>(i)
2x+3y=4 ------->(ii)
By elimination method
multiplying 2 in eq (i)
2(3x+2y=11)
6x+4y=22 ------>(iii)
multiplying 3 in eq (ii)
3(2x+3y=4)
6x+9y=12 -------->(iv)
subtracting eq (iii) from (iv)
= –5y=10
y= 10/–5
y= –2
putting the value of y in eq (i)
3x+2y=11
3x+2(–2)=11
3x–4=11
3x=11+4
3x=15
x=15/3
x=5
Therefore x= 5 and y= –2
Step-by-step explanation:
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