Solution of question nu . 20
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refer to the above attachment
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Given;
- Sec5A=Cosec(A-36)
- And 5A is an acute angle
To Prove;
- A=21
Solution;
- Sec5A=Cosec(A-36)
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We know that
- Cosec(90 - Ø) = secØ
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Then,
- Sec5A = cosec(A - 36)
- Cosec(90 - 5A) = cosec(A - 36)
- 90 - 5A = A - 36
- -5A-A= -36-90
- -6A= -126
- A= -126/-6
- A=21
#Answer with quality
#BAL
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