Solution of set
1<=|x-2|<=3 is
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Answer:
-2 < |x-3| - 4 < 2
-2+4 < |x-3| < 2+4
2 < |x-3| < 6
Now, if (x-3) > 0
We will get
2 < x-3 < 6
2+3 < x < 6+3
6 < x < 9
But, if (x-3) < 0
We will get
2 < -( x-3) < 6
Which implies, -6 < x-3 < -2
-6+3 < x < -2+3
-3 < x < 1
Which implies, x belongs to (-3,1) U (6,9)
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