solution of sseries118;182;186;222;?
Answers
Answered by
14
Answer:
226
Explanation:
118 , 182 , 186 , 222
The difference between two terms is as-
118 (64) 182 (4) 186 (36) 222
From this we get to know that the difference is square of the last digit
118 = 8^2 = 64 = (182-118)
182 = 2^2 = 4 = (186-182)
186 = 6^2 = 36 = (222-186)
So if we follow the trend
222 = 2^2 = 4 = (x-222)
x = 226
Answered by
6
Answer: the logic is si*k!
From the choice it seems, the answer is 226!
Explanation:
Stup*d logic it seems!
182-118 = 64, 8² - square of last digit of previous number
186-182= 4, 2²
Similarly, 8², 2², 6²...add 2² ---> 222+4= 226!
This won't strike in a minute just like that!
Similar questions