Question

solution of the cubic equation x^3-6x^2+11x-6=0

Answer 1

Given (x^3)-6(x^2)+11x-6=0
let x=1 is the factor of the equation
1 |1 -6 11 -6
| 0 1 -5 6
-----------------------
1 -5 6 0
hence x=1 is one of the factor
=>x^2-5x+6=0
=>x^2-2x-3x+6=0
=>x(x-2)-3(x-2)=0
=>(x-2)(x-3)=0
hence factor are (x-1)(x-2)(x-3)=0

Answer 2

Hey Matey ^^

Here's your answer
____________________________

x^3–6x^2+11x-6
=x^3-x^2–5x^2+5x+6x-6
=x^2(x-1)-5x(x-1)+6(x-1)
=(x-1)(x^2–5x+6)
=(x-1)(x^2–2x-3x+6)
=(x-1){x(x-2)-3(x-2)}
=(x-1){(x-2)(x-3)}
=(x-1)(x-2)(x-3)


Hope it helps ^_^