Math, asked by gyanendrakb, 1 month ago

Solution of the D.E y" – 4y + 4y = ex when solved
undetermined coefficients is
a) y = (C+ + C2) e2x + 2e - 1
b) y = (C+ C2 x) e2x + 4e* - 4
c) y = (C+ + C2 x) e2x + ex
d) y = (C1 + C2 x) ex + 4ex
Solution of the D.E y" + 3y' + 2y = 12x2 when solv
method of undetermined coefficients is
a) y = C1 et + C2 e2x + 2 - 11x + x2
b) y = C1 e-* + C2 e-2x + 18+ 21x + 3x2
c) y = C1 ex + C2 e - 2x + 11 + 18x + 2x2
l) y = C1 e - + C2 e - 2x + 21 – 18x + 6x2​

Answers

Answered by kushKumar09
0

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♤♡◇《 answer is c++ × cx2 +9x 》◇♡♤

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