Question

solution of the equation (D^3-2D+3D+5)y=0 is​

Answer 1

Answer:

Step-by-step explanation:

Given differential equation is

(D² - 3D + 2)y = 0

Auxiliary equation of above differential equation is

D² - 3D + 2 = 0

=> D² - 2D - D + 2 = 0

=> D(D - 2) - 1(D - 2) = 0

=> (D - 2)(D - 1) = 0

=> D = 2,1

Hence the general solution is given by

y = c₁e²ˣ + c₂eˣ