Math, asked by jitendrakumar76790, 15 days ago

Solution of the linear equation 8y+4 = 3(y-1)+7 is​

Answers

Answered by DeeznutzUwU
1

       \underline{\bold{Answer:}}

       0

       \underline{\bold{Step-by-step-explaination: }}

       \text{The given linear equation is }8y + 4 = 3(y-1) + 7

\implies \boxed{8y + 4 = 3(y) +3(-1) + 7}

\implies \boxed{8y + 4 = 3y - 3 + 7}

\implies \boxed{8y + 4 = 3y + 4}

\implies \boxed{8y + 4 -3y -4 =0}

\implies \boxed{5y =0}

\implies \boxed{y =\frac{0}{5} }

       \text{We know that } \frac{0}{a} = 0 \text{ , where }a \text{ is any number}

  \therefore \text{ }\boxed{y = 0}

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